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Q & A ... °Ô½ÃÆÇ  (Optimization)


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    ÀúÈñ KSTECÀÇ Á¦Ç°À̳ª ¼­ºñ½º¿¡ ´ëÇØ ±Ã±ÝÇϽŠÁ¡À̳ª ±â¼úÁö¿øÀ» ¿øÇϽô °í°´´ÔÀº ȸ»ç¸í,
    ºÎ¼­¸í, ¼º¸í, »ç¿ëÁ¦Ç°¸í, Á¦Ç° VERSIONÀ» ¸í½ÃÇÏ¿© Áֽñ⠹ٶø´Ï´Ù.

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¡Ø ÇØ´çµÇ´Â Á¦Ç°±ºÀ» ¼±ÅÃÇϽŠÈÄ ÇÏ°í ½ÍÀ¸½Å ¸»¾¸À» Àû¾î ÁֽʽÿÀ.

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QPµµ Ç®ÀÌ °¡´ÉÇÕ´Ï´Ù.
ÀÛ¼ºÀÚ
À̺¸Çå
ÀÛ¼ºÀÏ
2007-10-05
Á¶È¸¼ö 1137 È¸
÷ºÎÆÄÀÏ Ã·ºÎµÈ ÆÄÀϾøÀ½.
ILOG´Â CP¿Í CPLEX, OPL µîÀÇ Á¦Ç°µéÀÌ ÀÖ½À´Ï´Ù.

CPLEX »ç¿ë½Ã,

ù¹ø¹®Á¦ ºÒ°¡.

ÀϹÝÀûÀ¸·Î ¼­·Î ´Ù¸¥ º¯¼öÀÇ °öÀº Áö¿øÇÏÁö ¾Ê½À´Ï´Ù.

´ÙÀ½°ú °°ÀÌ
Minimize a + b + 1/2(a2 + 4ab + 7b2)
subject to a + b ¡Ã 10
with these bounds a ¡Ã 0 and b ¡Ã 0

º¯¼ö a, bÀÇ ¿¬»êÀÌ Á¦°ö½ÄÀ¸·Î Ç¥Çö ÇÒ ¼ö ÀÖÀ»°æ¿ì Ç®ÀÌ °¡´ÉÇÕ´Ï´Ù.

µÎ¹øÀç¹®Á¦
x1 = 1
x2 = 1.5
obj =11.5

////
ù¹øÂ° ¹®Á¦ÀÇ °æ¿ì ILOG CP¸¦ »ç¿ëÇØ Ç®ÀÌ °¡´ÉÇÕ´Ï´Ù.

CP »ç¿ë½Ã(solver) ù¹øÂ° ¹®Á¦
X1 = 1.00563
X2 = 1.98872
obj= 1.9999

°ü·Ã±Û º¸±â
"QPµµ Ç®ÀÌ °¡´ÉÇÕ´Ï´Ù."¿Í(°ú) °ü·ÃµÈ ±ÛÀÌ  2°Ç ÀÖ½À´Ï´Ù.
ilog·Î ÄÚµùÀÌ µÇ³ª¿ä? ¹ÚÁ¾È­ 2007-10-05
QPµµ Ç®ÀÌ °¡´ÉÇÕ´Ï´Ù. À̺¸Çå 2007-10-05
   [RE]QPµµ Ç®ÀÌ °¡´ÉÇÕ´Ï´Ù. ¹ÚÁ¾È­ 2007-10-11